If MO bisects LMN, then LMO and NMO are equal. So 8x-23=2x+37. 8x-23=2x+ 37. 6x=60. x=10. LMN=8x-23+2x+37. LMN=10x+14.
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m LMN. ∠ . O. L. M 6x – 6. Assume B is the midpoint of and D is the midpoint of. 20. Solve for x giv MO. bisects LMN, mLMO 6x 22, and.
math indirect measurement Answer: 1 📌📌📌 question Plz with ! ray mo bisects ∠lmn, m∠lmo=6x-20 and m∠nmo=2x+36.
In the figure (not drawn to scale), MO bisects ∠LMN, m LMO x∠ = −17 32, and m NMO x∠ = +144. Solve for x and find m LMN∠ .
Mo bisects lmn m lmn 6x-28 m lmo x+34. find m. Answers (1) One of the primary difference between prokaryotic cells and eukaryotic cells is. line MO bisects angle LMN, angle LMN = 6x - 28, angle LMO = x + 34.
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____ 7. m∠JHI = (2x + 7)° and m∠GHI = (8x − 2)° and m∠JHG = 65°. Find m∠ JHI and In the figure (not drawn to scale), MO. →⎯ ⎯ ⎯ bisects ∠LMN, m∠ LMO = (13x − 31)°, and m∠NMO = (x + 53)°. Solve for x and find If m∠JOK= 28° and m
MO. →. bisects ∠LMN, m∠LMO = 6x − 22, and m∠NMO = 2x + 34. l is parallel to m.
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The diagram is not to scale. answer choices 7. In the figure (not drawn to scale), MO bisects ∠LMN, m LMO x∠ = −17 32, and m NMO x∠ = +144. Solve for x and find m LMN∠ . L O M N [A] 7, 43 [B] 11, 310 [C] 7, 87 [D] 11, 219 8.
T(6, 17) is the midpoint of CD. The coordinates of.
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6x – 18 c. 3x – 9 d. 1.5 x – 4.5 ____ 18. MO → bisects ∠LMN, m∠LMO = 6x − 22, and m∠NMO = 2x + 34.