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In ABC is a quadrant of a circle of radius 14 cm and a semicircle is drawn with BC. as diameter. Find the area of the shade region. Q.3 In the fig., ABC is a quadrant of a circle of radius 14 cm and a semicircle is drawn with BC as diameter. Find the area of the shaded region. [Foreign 2008, Delhi 2008 C] Area of a trapezium = 24.5 cm212 AD + BC X AB = 24.5 Cm212 10+4 X AB = 24.5AB = 3.5 cm r= 3.5 cmAreao of quadrant = 14x π r2 = 0.25 x 227 x 3.5 x 3.5 = 9.625 cm2 The area of shaded region = 24. 5 - 9.625 = 14.875 cm2 In the given figure, ABCD is a square of side 4 cm. A quadrant of a circle of radius 1 cm is drawn at each vertex of the square and a circle of diameter 2 cm is also drawn.

As abcd is a quadrant of a circle

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FIND THE AREA OF SADED REGION? 29 In the below figure ABCD is a quadrant of a circle of radius 28 cm and a from MATH 2030 at Indian Institute of Technology, Chennai In Fig. 12.33, ABC is a quadrant of a circle of radius 14 cm and a semicircle is drawn with BC as diameter.

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Find the area of the shaded region.

Find the area of the shaded region. Area of shaded region = Area of semicircle BEC (Area of quadrant ABDC Area of ABC) Area quadrant ABDC Radius = 14 cm Area of quadrant ABDC = 1/4 (area of circle) = 1/4 ( r2) = 1/4 22/7 (14)^2 = 1/4 22/7 14 14 = 154 cm2 Area triangle ABC Since ABDC is a quadrant BAC = 90 Hence ABC is a right triangle with Base AC & Height AB In the figure ABCD is a quadrant of a circle of radius 2 8 cm and a semi circle BEC is drawn with BC as diameter . Find the area of the shaded region.( Use π = 7 2 2 ) ABCD is a quadrent of a circle of radius 28cm, and a semicircle BEC is drawn with BC as diameter. The area of the shaded region is 392 cm². Stepwise explanation is given below: - It is given that, radius of the circle = AB = AC = 28 cm - Area of quadrant ABDC = 1/4×π×r² = (1/4×22/7×28×28) cm² =22× 28= 616 cm² In the figure, ABC is a quadrant of a circle of radius 14cm, and a semicircle is drawn with BC as diameter. Find the area of the shaded region.
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[π = 3.14] Advertisement Remove all ads In figure, ABCD is a square of side 4 cm. A quadrant of a circle of radius 1 cm is drawn at each vertex of the square and a circle of diameter 2 cm is also drawn. Find the area of the shaded region ABCD is a quadrent of a circle of radius 28cm, and a semicircle BEC is drawn with BC as diameter.

Draw rectangles, circles, triangles. Draw trend lines, horizontal lines, vertical lines, fib lines, quadrant lines, cycle lines, or channel lines. Draw ABCD, XABCD, Elliot Impulse and Corrective wave patterns.
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DISC is based on four quadrants of personality, which dates back to 444 B.C. Given: Radius (r) of the circle = AB = AC = 28 cm. Area of quadrant ABPC = 1/4×π×r².

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308 c m 2 198 c m 2 ABCD is a quadrent of a circle of radius 28cm, and a semicircle BEC is drawn with BC as diameter. The area of the shaded region is 392 cm².